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RE: [amibroker] Re: DT's Ct prediction for the Ti3



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Dt, you are going to shoot me...but we are so close that i take that risk!
Making a slight change to your code I added a Param() to modify the close
and I changed the Ref(C,-3) to Ref(Ti3,-3) - no significant changes thus.
Now click on any bar and change the Close to the point where the two Ti3s
(Red and Black) cross, at this point the C (Black)should be equal to the
predicted Ct (Green should meet Black). It does not. Can you explain where i
went wrong?

many thanks again,
herman

PriceOffSet = Param("Price offset",0,-2,2,0.001);
BarNum = SelectedValue(BarIndex());CursorBar = BarNum == BarIndex();
ParamPrice = C + PriceOffSet;C = IIf(CursorBar, ParamPrice, C);
Plot(C,Date()+", C",colorBlack,8);
p=5;s=0.7;f=2/(p+1);R=1-f;
e1=EMA(C,p);
e2=EMA(e1,p);
e3=EMA(e2,p);
e4=EMA(e3,p);
e5=EMA(e4,p);
e6=EMA(e5,p);
C1=-s^3;
C2=3*s^2*(1+s);
C3=-3*s*(s+1)^2;
C4=(1+s)^3;
Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
Plot(Ti3,"Ti3",colorWhite,1);
Ti3t=Ref(Ti3,-3);//the condition
Plot(Ti3t,"Ti3t...",colorRed,8);
//the calculation
Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
(f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
(f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
Plot(Ct,"Ct...",5,8);
PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);

-----Original Message-----
From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@xxxxxxxxx]
Sent: Wednesday, October 27, 2004 8:16 AM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Re: DT's Ct prediction for the Ti3



Scenario III
If the next bar Ti3 should be equal to the Close 3 bars ago, then
calculate the next bar Close Ct.

We shall work again the scenario II formula, since we know Ti3t and
we ask for Ct.

Plot(C,Date()+", C",colorBlack,8);
p=5;s=0.7;f=2/(p+1);R=1-f;
e1=EMA(C,p);
e2=EMA(e1,p);
e3=EMA(e2,p);
e4=EMA(e3,p);
e5=EMA(e4,p);
e6=EMA(e5,p);
C1=-s^3;
C2=3*s^2*(1+s);
C3=-3*s*(s+1)^2;
C4=(1+s)^3;
Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
Plot(Ti3,"Ti3",colorWhite,1);
Ti3t=Ref(C,-3);//the condition
Plot(Ti3t,"Ti3t...",colorRed,8);
//the calculation
Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
(f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
(f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
Plot(Ct,"Ct...",5,8);
PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);

In CSCO chart I see a yellow circle on Feb3, 2004.
For this date we read Ct=24.06, Ti3t=25.96.It means : If the next bar
Close is 24.06, then the next bar Ti3 will be equal to 25.96.
The next bar close was indeed 24.08 and the next bar Ti3 was 25.96
I hope it is clear, I have nothing more to add.
Dimitris
--- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
wrote:
>
> Until then, let us see how it works.
>
> Scenario I:
> If the next bar CSCO close is 19, calculate the next bar Ti3.
>
> Plot(C,Date()+", C",colorBlack,8);
> p=5;s=0.7;f=2/(p+1);R=1-f;
> e1=EMA(C,p);
> e2=EMA(e1,p);
> e3=EMA(e2,p);
> e4=EMA(e3,p);
> e5=EMA(e4,p);
> e6=EMA(e5,p);
> C1=-s^3;
> C2=3*s^2*(1+s);
> C3=-3*s*(s+1)^2;
> C4=(1+s)^3;
> Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> Plot(Ti3,"Ti3",colorWhite,1);
> Ct=19;//the next bar Close condition
> Plot(Ct,"Ct",colorBrightGreen,8);
> //the next bar Ti3 calculation
> Ti3t=(C1*f^6+C2*f^5+C3*f^4+C4*f^3)*Ct+
> (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+(c1*f^4+c2*f^3+c3*f^2+c4*f)
> *e2+(c1*f^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+(c1*f+c2*1)
> *e5+c1*e6);
> Plot(Ti3t,"Ti3t...",colorRed,8);
>
> On Aug17, for example, we read Ti3t=18.26
> On the next bar, Aug18, the actual close is C=18.99 and the Ti3 is
> indeed 18.26
>
> Scenario II
> If the next CSCO bar Ti3 is 19, then calculate the next bar close.
>
> Plot(C,Date()+", C",colorBlack,8);
> p=5;s=0.7;f=2/(p+1);R=1-f;
> e1=EMA(C,p);
> e2=EMA(e1,p);
> e3=EMA(e2,p);
> e4=EMA(e3,p);
> e5=EMA(e4,p);
> e6=EMA(e5,p);
> C1=-s^3;
> C2=3*s^2*(1+s);
> C3=-3*s*(s+1)^2;
> C4=(1+s)^3;
> Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> Plot(Ti3,"Ti3",colorWhite,1);
> Ti3t=19;//the next bar Ti3 condition
> Plot(Ti3t,"Ti3t...",colorRed,8);
> //the next bar Ct calculation
> Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
> (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> Plot(Ct,"Ct...",colorbrightgreen,8);
>
> On Oct07 we see that we need a next bar Ct=18.75, in order to have
a
> next bar Ti3t=19.
> On the next bar, Oct8, C=18.78 and Ti3=19.00
>
> Dimitris
>
> --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
<TSOKAKIS@xxxx>
> wrote:
> >
> > Herman,
> > Athens would not be a bad idea.
> > 28 Celsius now [20min before 12:00], it will be around 30 some h
> > later.
> > The menu is broiled fresh fish and will be served 4h later.
> > Since the fisher and the broiler is the same person, the
> word "fresh"
> > is guaranteed.
> > 10-year red wine will be also available [unlimited quantity and
> free
> > of charge].
> > It would be, perhaps, the ideal condition to discuss Ti3 details.
> > Although this message looks [strongly] into the future, it is not
> > dangerous as the zig functions.
> > Dimitris
> > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
> > <psytek@xxxx> wrote:
> > > DT, your patience is much appreciated, it is 4:00 am here so
I'll
> > get some
> > > sleep first and will study your formulas in the (later)
morning,
> > thanks for
> > > the extra explanations, I think they will help. i have a strong
> gut
> > feeling
> > > your formulas really give me what i want  - I may just be a bit
> > overwhelmed
> > > by all the terms, they look a bit intimidating :-)
> > >
> > > Thanks again DT, I sure will enjoy working on it later.
> > > herman
> > >   -----Original Message-----
> > >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > >   Sent: Wednesday, October 27, 2004 3:13 AM
> > >   To: amibroker@xxxxxxxxxxxxxxx
> > >   Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> > >
> > >
> > >
> > >   Herman,
> > >   Do not add this "NOT when the Ct crosses anything", it makes
> > things
> > >   complicated without reason. No Ct touch was used in the
> > >   http://finance.groups.yahoo.com/group/amibroker/message/72276
> > >   solution.
> > >   Ct is the [unconditional] next bar Close, as already
explained.
> > >   Ti3Ct is the [unconditional] next bar Ti3C.
> > >   The formulas
> > >
> > >   Ti3Ct=(C1*f^6+C2*f^5+C3*f^4+C4*f^3)*Ct+
> > >   (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+
> > (c1*f^4+c2*f^3+c3*f^2+c4*f)
> > >   *e2+(c1*f^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+
> (c1*f+c2*1)
> > >   *e5+c1*e6);
> > >   and
> > >   Ct=(Ti3Ct-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> > >   (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
> > >   (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > >
> > >   are nothing but mathematical definitions.
> > >   The first gives the Ti3Ct as a function of Ct.Give a value to
> Ct
> > and
> > >   you will get the Ti3Ct.
> > >   The second gives the Ct as a function of Ti3Ct. Give a value
to
> > Ti3Ct
> > >   and you will get Ct.
> > >   See also the verification in
> > >   http://finance.groups.yahoo.com/group/amibroker/message/72290
> > >   Dimitris
> > >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
> > >   <psytek@xxxx> wrote:
> > >   > Thank you DT,
> > >   >
> > >   > The problem is different. We need to know the value of
> > tomorrow's
> > >   Ct when
> > >   > two OTHER arrays cross, NOT when the Ct crosses anything:
Ct
> is
> > not
> > >   required
> > >   > to touch any line. I do not know how to explain it better:
the
> > >   objective is
> > >   > to know at what value of Ct the other two functions cross,
> i.e.
> > >   find Ct when
> > >   > a F1(Ct) touches F2(Ref(Array,-1)). This is probably a more
> > useful
> > >   > application than having the raw C touch any line because
the
> C
> > is
> > >   subject to
> > >   > a lot of noise and would give many false signals.  I think
> your
> > >   innovative
> > >   > math functions provide the solution for this problem but i
> can't
> > >   figure out
> > >   > how, I hoped my code would illustrated the problem more
> > clearly...
> > >   Forgive
> > >   > me if i am just plain dumb and the solution is staring at
me.
> > >   >
> > >   > Anyway, thanks very much for your time DT,
> > >   > best regards,
> > >   > herman.
> > >   >
> > >   >
> > >   >
> > >   >   -----Original Message-----
> > >   >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > >   >   Sent: Tuesday, October 26, 2004 2:08 AM
> > >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> > >   >
> > >   >
> > >   >
> > >   >   Herman,
> > >   >   The formula is correct and gives the next bar close Ct as
a
> > >   function
> > >   >   of tomorrow´s Ti3Ct.
> > >   >   When Ti3Ct value is known [or equal to another function]
> then
> > Ct
> > >   is
> > >   >   calculated.
> > >   >   For a simple verification, set
> > >   >   Ti3Ct=Ref(Ti3C,1);
> > >   >   and then Ct will be EXACTLY the Ref(C,1).
> > >   >
> > >   >   Plot(C,"C",colorBlack,1);
> > >   >   periods=5;s=0.7;f=2/(periods+1);R=1-f;
> > >   >   //the Ti3C
> > >   >   price=C;
> > >   >   e1C=EMA(price,periods);
> > >   >   e2C=EMA(e1C,Periods);
> > >   >   e3C=EMA(e2C,Periods);
> > >   >   e4C=EMA(e3C,Periods);
> > >   >   e5C=EMA(e4C,Periods);
> > >   >   e6C=EMA(e5C,Periods);
> > >   >   c1=-s*s*s;
> > >   >   c2=3*s*s+3*s*s*s;
> > >   >   c3=-6*s*s-3*s-3*s*s*s;
> > >   >   c4=1+3*s+s*s*s+3*s*s;
> > >   >   Ti3C=c1*e6C+c2*e5C+c3*e4C+c4*e3C;
> > >   >   Ti3Ct=Ref(Ti3C,1);// condition
> > >   >   //the Ct as a function of Ti3Ct
> > >   >   Ct=(Ti3Ct-R*(c1*
(f^5*e1C+f^4*e2C+f^3*e3C+f^2*e4C+f*e5C+e6C)
> > +c2*
> > >   >   (f^4*e1C+f^3*e2C+f^2*e3C+f*e4C+e5C)+c3*
> > (f^3*e1C+f^2*e2C+f*e3C+e4C)
> > >   +c4*
> > >   >   (f^2*e1C+f*e2C+e3C)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > >   >   Plot(Ref(Ct,-1),"Ct",colorRed,8);
> > >   >
> > >   >   Dimitris
> > >   >
> > >   >
> > >   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
> > >   >   <psytek@xxxx> wrote:
> > >   >   > Hello DT,
> > >   >   >
> > >   >   > I really appreciate your help with this however is that
> your
> > >   >   solution looks
> > >   >   > somewhat the same but isn't accurate...perhaps you
> > misunderstood
> > >   >   and are
> > >   >   > calculating something else...
> > >   >   >
> > >   >   > The best way for me to illustrate my need is with a
> generic
> > >   >   iterative
> > >   >   > solution. Sorry to impose on you DT but to see how the
> > result
> > >   >   differs you
> > >   >   > have to display both your solution and mine. When you
have
> > >   loaded
> > >   >   the demo
> > >   >   > code below, click on any bar and open the Param()
window.
> > Then
> > >   >   apply an
> > >   >   > offset to the selected close price until you see the
two
> T3s
> > >   (white
> > >   >   and
> > >   >   > black) cross, at that point the C price is exactly on
the
> > >   Predicted
> > >   >   Close
> > >   >   > price (Red). This is not the case with your formula.
Note
> > that I
> > >   >   moved the
> > >   >   > Red predicted value forward one bar to allow easier
> > comparison
> > >   to
> > >   >   the Close
> > >   >   > and show a little square when the target is hit. The key
> > >   >   requirement of
> > >   >   > course it that C falls exactly on the predicted value
> when
> > the
> > >   T3s
> > >   >   cross -
> > >   >   > this doesn't happen with your indicator.
> > >   >   >
> > >   >   > With EOD data and restricting the calculation to the
> display
> > >   area
> > >   >   only, my
> > >   >   > solutions works OK, but i need a continuous indicator
for
> > the
> > >   >   entire data RT
> > >   >   > history, this means about 100K bars. If your formula
> worked
> > it
> > >   >   would enable
> > >   >   > me to do that!!!
> > >   >   >
> > >   >   > Any change of making your solution match mine?
> > >   >   >
> > >   >   > thanks again DT,
> > >   >   > herman.
> > >   >   >
> > >   >   >
> > >   >   > --------------------------------------------------------
--
> --
> > ----
> > >   ----
> > >   >   --------
> > >   >   > ----
> > >   >   >
> > >   >   > SetBarsRequired(1000000,1000000);
> > >   >   >
> > >   >   > function Ti3(array,p,s)
> > >   >   >  {
> > >   >   >  f=2/(p+1);
> > >   >   >  e1=EMA(array,p);
> > >   >   >  e2=EMA(e1,p);
> > >   >   >  e3=EMA(e2,p);
> > >   >   >  e4=EMA(e3,p);
> > >   >   >  e5=EMA(e4,p);
> > >   >   >  e6=EMA(e5,p);
> > >   >   >  c1=-s*s*s;
> > >   >   >  c2=3*s*s+3*s*s*s;
> > >   >   >  c3=-6*s*s-3*s-3*s*s*s;
> > >   >   >  c4=1+3*s+s*s*s+3*s*s;
> > >   >   >  T3=c1*e6+c2*e5+c3*e4+c4*e3;
> > >   >   >  return T3;
> > >   >   >  }
> > >   >   >
> > >   >   > function ReferenceFunction( ReferenceArray )
> > >   >   >  {
> > >   >   >  global T3Periods, T3Sensitivity, ResetReference;
> > >   >   >  R = Ti3( ReferenceArray, T3Periods ,T3Sensitivity);
> > >   >   >  return R;
> > >   >   >  }
> > >   >   >
> > >   >   > function TestFunction( TestArray )
> > >   >   >  {
> > >   >   >  global T3Periods, T3Sensitivity, ResetReference;
> > >   >   >  R = Ti3( TestArray, T3Periods ,T3Sensitivity);
> > >   >   >  return R;
> > >   >   >  }
> > >   >   >
> > >   >   > function GetTriggerPrice( ReferenceArray, TestArray,
> > TestBarNum,
> > >   >   T3Period,
> > >   >   > T3Sensitivity )
> > >   >   >  {
> > >   >   >  Precision  = 0.0001;
> > >   >   >
> > >   >   >  RefArray  = ReferenceFunction( ReferenceArray );
> > >   >   >  RefValue  = RefArray[TestBarNum ];
> > >   >   >
> > >   >   >  TestValue = TestArray[TestBarNum];
> > >   >   >  TestIncr  = TestValue/3;
> > >   >   >
> > >   >   >  do {
> > >   >   >   TestArray[TestBarNum ]  = TestValue;
> > >   >   >   T3t     = TestFunction( TestArray);
> > >   >   >   TodaysT3   = T3t[TestBarNum ];
> > >   >   >   if( abs(TodaysT3-RefValue) < Precision );
> > >   >   >   else if(TodaysT3< RefValue) TestValue= TestValue+
> > TestIncr ;
> > >   >   >   else TestValue= TestValue- TestIncr ;
> > >   >   >   TestIncr = TestIncr /2;
> > >   >   >   Error = abs(TodaysT3- RefValue);
> > >   >   >   } while ( Error > Precision );
> > >   >   >
> > >   >   >  return TestArray[TestBarNum ];
> > >   >   >  }
> > >   >   >
> > >   >   > PriceOffSet = Param("Price offset",0,-2,2,0.001);
> > >   >   > BarNum = SelectedValue(BarIndex());
> > >   >   > CursorBar = BarNum == BarIndex();
> > >   >   > ParamPrice = C + PriceOffSet;
> > >   >   > C = IIf(CursorBar, ParamPrice, C);
> > >   >   > ReferenceArray = Ref(H,-1);
> > >   >   > TestArray = C;
> > >   >   > T3Periods = 3;
> > >   >   > T3Sensitivity = 0.7;
> > >   >   >
> > >   >   > FirstVisibleBar = Status( "FirstVisibleBar");
> > >   >   > Lastvisiblebar = Status("LastVisibleBar");
> > >   >   > TP=Null;
> > >   >   > for( b = Firstvisiblebar; b < Lastvisiblebar AND b <
> > BarCount;
> > >   b++)
> > >   >   >  {
> > >   >   >  TP[b] = GetTriggerPrice( ReferenceArray, TestArray, b,
> > >   T3Periods,
> > >   >   > T3Sensitivity );
> > >   >   >  }
> > >   >   >
> > >   >   > TargetHit = IIf(abs(C-TP) < 0.01,1,Null);
> > >   >   > Plot(C,"C",1,128);
> > >   >   > Plot(Ti3( ReferenceArray,
> > >   >   T3Periods ,T3Sensitivity),"ReferenceArray",1,1);
> > >   >   > Plot(Ti3( TestArray,
> > T3Periods ,T3Sensitivity),"TestArray",2,1);
> > >   >   > PlotShapes(TargetHit*shapeHollowSquare,9,0,TP,0);
> > >   >   > Plot(TP,"TP",4,1);
> > >   >   >
> > >   >   > --------------------------------------------------------
--
> --
> > ----
> > >   ----
> > >   >   --------
> > >   >   > ----
> > >   >   >
> > >   >   >
> > >   >   >
> > >   >   >
> > >   >   >
> > >   >   >   -----Original Message-----
> > >   >   >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > >   >   >   Sent: Monday, October 25, 2004 3:04 PM
> > >   >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   >   Subject: [amibroker] Re: DT's Ct prediction for the
Ti3
> > >   >   >
> > >   >   >
> > >   >   >
> > >   >   >   Herman,
> > >   >   >   As I wrote in previous post, Ct is a function of
Ti3Ct
> > [and
> > >   vice
> > >   >   >   versa]
> > >   >   >   In your example, Ti3C and Ti3H should be calculated
> > >   separately, to
> > >   >   >   avoid any confusion.
> > >   >   >   The expected next bar Close Ct would be
> > >   >   >
> > >   >   >   Plot(C,"C",colorBlack,8);
> > >   >   >   periods=5;s=0.7;f=2/(periods+1);R=1-f;
> > >   >   >   //the Ti3H
> > >   >   >   price=H;
> > >   >   >   e1H=EMA(price,periods);
> > >   >   >   e2H=EMA(e1H,Periods);
> > >   >   >   e3H=EMA(e2H,Periods);
> > >   >   >   e4H=EMA(e3H,Periods);
> > >   >   >   e5H=EMA(e4H,Periods);
> > >   >   >   e6H=EMA(e5H,Periods);
> > >   >   >   c1=-s*s*s;
> > >   >   >   c2=3*s*s+3*s*s*s;
> > >   >   >   c3=-6*s*s-3*s-3*s*s*s;
> > >   >   >   c4=1+3*s+s*s*s+3*s*s;
> > >   >   >   Ti3H=c1*e6H+c2*e5H+c3*e4H+c4*e3H;
> > >   >   >   //Plot(Ti3H,"Ti3H",1,1);
> > >   >   >   //the Ti3C
> > >   >   >   price=C;
> > >   >   >   e1C=EMA(price,periods);
> > >   >   >   e2C=EMA(e1C,Periods);
> > >   >   >   e3C=EMA(e2C,Periods);
> > >   >   >   e4C=EMA(e3C,Periods);
> > >   >   >   e5C=EMA(e4C,Periods);
> > >   >   >   e6C=EMA(e5C,Periods);
> > >   >   >   Ti3C=c1*e6C+c2*e5C+c3*e4C+c4*e3C;
> > >   >   >   //Plot(Ti3C,"Ti3C",2,1);
> > >   >   >   Ti3Ct=Ti3H;//your condition:the next bar Ti3C is
equal
> to
> > >   todays
> > >   >   Ti3H
> > >   >   >   //the Ct as a function of Ti3Ct
> > >   >   >   Ct=(Ti3Ct-R*(c1*
> > (f^5*e1C+f^4*e2C+f^3*e3C+f^2*e4C+f*e5C+e6C)
> > >   +c2*
> > >   >   >   (f^4*e1C+f^3*e2C+f^2*e3C+f*e4C+e5C)+c3*
> > >   (f^3*e1C+f^2*e2C+f*e3C+e4C)
> > >   >   +c4*
> > >   >   >   (f^2*e1C+f*e2C+e3C)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > >   >   >   Plot(Ct,"Ct",colorRed,8);
> > >   >   >
> > >   >   >   For periods>10 the condition is quite rare.
> > >   >   >   Dimitris
> > >   >   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den
> Bergen"
> > >   >   >   <psytek@xxxx> wrote:
> > >   >   >   > In my requirements there is only one unknown, the
> next
> > day
> > >   Ct as
> > >   >   >   the other
> > >   >   >   > Ti3 was using the previous bar's value. The
equation
> is
> > >   >   solvable by
> > >   >   >   > iteration however it is too slow for Real Time
data,
> > where
> > >   in a
> > >   >   >   backtests i
> > >   >   >   > want to process 100,000 bars. The problem could
also
> be
> > >   stated,
> > >   >   >   since both
> > >   >   >   > Ti3s have the same value when crossing, and
assigning
> > >   arbitrary
> > >   >   >   familiar
> > >   >   >   > price arrays to Array1 and Array2, as:
> > >   >   >   >
> > >   >   >   > Ti3( ref(H,-1), period, sensitivity )  =  Ti3( C,
> > period,
> > >   >   >   sensitivity )
> > >   >   >   >
> > >   >   >   > and solving for C. In this equation C is the only
> > unknown
> > >   >   because H
> > >   >   >   is
> > >   >   >   > yesterday's known value. Your earlier solutions are
> > close to
> > >   >   this
> > >   >   >   but i
> > >   >   >   > haven't been able to modify them to this
requirement.
> > Note
> > >   that
> > >   >   >   periods and
> > >   >   >   > sensitivities are the same on both sides of the
> > equation.
> > >   >   >   >
> > >   >   >   > Best regards,
> > >   >   >   > herman
> > >   >   >   >
> > >   >   >   >
> > >   >   >   >   -----Original Message-----
> > >   >   >   >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > >   >   >   >   Sent: Monday, October 25, 2004 6:58 AM
> > >   >   >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   >   >   Subject: [amibroker] Re: DT's Ct prediction for
the
> > Ti3
> > >   >   >   >
> > >   >   >   >
> > >   >   >   >
> > >   >   >   >   To be more specific:
> > >   >   >   >   Ti3t, the next bar Ti3 of an array, is ALWAYS a
> > [known]
> > >   >   function
> > >   >   >   of
> > >   >   >   >   the next bar array value arrayt.
> > >   >   >   >   Arrayt is NOT ALWAYS a [known] function of the
next
> > bar
> > >   Close
> > >   >   Ct.
> > >   >   >   >   Dimitris
> > >   >   >   >   PS : If you could be more specific about array1,
> > array2 we
> > >   >   could
> > >   >   >   >   probably come to some result...
> > >   >   >   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den
> > Bergen"
> > >   >   >   >   <psytek@xxxx> wrote:
> > >   >   >   >   > Thank you Dt.
> > >   >   >   >   >
> > >   >   >   >   > herman
> > >   >   >   >   >   -----Original Message-----
> > >   >   >   >   >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > >   >   >   >   >   Sent: Monday, October 25, 2004 6:41 AM
> > >   >   >   >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   >   >   >   Subject: [amibroker] Re: DT's Ct prediction
for
> > the
> > >   Ti3
> > >   >   >   >   >
> > >   >   >   >   >
> > >   >   >   >   >
> > >   >   >   >   >   Herman,
> > >   >   >   >   >   There is no answer for this general question.
> > >   >   >   >   >   Some arrays may be RevEnged [RSI, Ti3], some
> > others
> > >   not
> > >   >   >   [StochD].
> > >   >   >   >   >   The next bar RSI is a function of the next
bar
> > Close
> > >   Ct,
> > >   >   the
> > >   >   >   next
> > >   >   >   >   bar
> > >   >   >   >   >   StochD is [unfortunately] a function of Ht,
Lt
> > and Ct.
> > >   >   >   >   >   Dimitris
> > >   >   >   >   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van
> den
> > >   Bergen"
> > >   >   >   >   >   <psytek@xxxx> wrote:
> > >   >   >   >   >   > Thank you DT, I tried this code but it
> requires
> > >   that pb
> > >   >   is
> > >   >   >   >   greater
> > >   >   >   >   >   than pa
> > >   >   >   >   >   > and also it uses C in both Ti3s. I am
looking
> > for a
> > >   >   sulution
> > >   >   >   >   where
> > >   >   >   >   >   pa==pb
> > >   >   >   >   >   > and we use different price arrays.
> > >   >   >   >   >   >
> > >   >   >   >   >   > best regards,
> > >   >   >   >   >   > herman
> > >   >   >   >   >   >
> > >   >   >   >   >   >
> > >   >   >   >   >   >
> > >   >   >   >   >   >
> > >   >   >   >   >   >   -----Original Message-----
> > >   >   >   >   >   >   From: DIMITRIS TSOKAKIS
> [mailto:TSOKAKIS@x...]
> > >   >   >   >   >   >   Sent: Monday, October 25, 2004 1:57 AM
> > >   >   >   >   >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   >   >   >   >   Subject: [amibroker] Re: DT's Ct
prediction
> > for
> > >   the
> > >   >   Ti3
> > >   >   >   >   >   >
> > >   >   >   >   >   >
> > >   >   >   >   >   >
> > >   >   >   >   >   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman
> van
> > den
> > >   >   Bergen"
> > >   >   >   >   >   >   <psytek@xxxx> wrote:
> > >   >   >   >   >   >   > DT, I am not sure i understand the
> Ti3t...
> > what
> > >   i am
> > >   >   >   trying
> > >   >   >   >   to
> > >   >   >   >   >   find
> > >   >   >   >   >   >   out is
> > >   >   >   >   >   >   > what tomorrows closing price would be
to
> > cause
> > >   the
> > >   >   >   crossing
> > >   >   >   >   of
> > >   >   >   >   >   two
> > >   >   >   >   >   >   Ti3
> > >   >   >   >   >   >   > functions.
> > >   >   >   >   >   >
> > >   >   >   >   >   >   Herman,
> > >   >   >   >   >   >   this specific question is already in
> > >   >   >   >   >   >
> > http://finance.groups.yahoo.com/group/amibroker-
> > >   >   >   ts/files/A%
> > >   >   >   >   20Ti3%
> > >   >   >   >   >   >   20application/
> > >   >   >   >   >   >   "Cross(Ti3a,Ti3b) predictions.txt"
> > >   >   >   >   >   >   Dimitris
> > >   >   >   >   >   >   For example:
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   > F1 = T3( Array1, 3, 0.8 );
> > >   >   >   >   >   >   > F2 = T3( ref(Array2,-1), 3, 0.8 );
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   > Array1 and Array2 are two different
> arrays
> > and
> > >   >   could be
> > >   >   >   any
> > >   >   >   >   >   type of
> > >   >   >   >   >   >   > indicator array. For development you
can
> > plug in
> > >   >   any of
> > >   >   >   the
> > >   >   >   >   OHLC
> > >   >   >   >   >   >   arrays, but
> > >   >   >   >   >   >   > you cannot use the same price array for
> both
> > >   >   function
> > >   >   >   >   calles.
> > >   >   >   >   >   >   > The Periods and Sensitivities are the
> same
> > for
> > >   both
> > >   >   T3
> > >   >   >   >   function
> > >   >   >   >   >   >   calls.
> > >   >   >   >   >   >   > F2 is based on yesterdays values, F1 is
> > based on
> > >   >   todays
> > >   >   >   >   values.
> > >   >   >   >   >   >   > I would like to calculate tomorrows
value
> > for
> > >   Array1
> > >   >   >   that
> > >   >   >   >   would
> > >   >   >   >   >   >   cause the
> > >   >   >   >   >   >   > two functions to cross: cross(F1, F2).
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   > Do you think this is possible?
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   > thanks for you help DT!
> > >   >   >   >   >   >   > herman
> > >   >   >   >   >   >   >   -----Original Message-----
> > >   >   >   >   >   >   >   From: DIMITRIS TSOKAKIS
> > [mailto:TSOKAKIS@x...]
> > >   >   >   >   >   >   >   Sent: Saturday, October 23, 2004 5:34
AM
> > >   >   >   >   >   >   >   To: amibroker@xxxxxxxxxxxxxxx
> > >   >   >   >   >   >   >   Subject: [amibroker] Re: DT's Ct
> > prediction
> > >   for
> > >   >   the
> > >   >   >   Ti3
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   Herman,
> > >   >   >   >   >   >   >   Ti3t (the next bar Ti3) is a direct
> > function
> > >   of
> > >   >   the
> > >   >   >   next
> > >   >   >   >   bar
> > >   >   >   >   >   >   Close Ct.
> > >   >   >   >   >   >   >   Ti3t=
> > >   >   >   >   >   >   >   c1*(f*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+
> > >   >   >   >   >   >   >   (1-f)*e2)+(1-f)*e3)+(1-f)*e4)+(1-f)
*e5)+
> > (1-f)
> > >   *e6)+
> > >   >   >   >   >   >   >   c2*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)
*e2)
> +
> > (1-f)
> > >   *e3)
> > >   >   +
> > >   >   >   >   >   >   >   (1-f)*e4)+(1-f)*e5)+
> > >   >   >   >   >   >   >   c3*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+
> (1-
> > f)
> > >   *e3)+
> > >   >   (1-f)
> > >   >   >   *e4)+
> > >   >   >   >   >   >   >   c4*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-
f)
> > *e3);
> > >   >   >   >   >   >   >   If I understand your question, you
want
> to
> > >   solve
> > >   >   Ct
> > >   >   >   for
> > >   >   >   >   any
> > >   >   >   >   >   given
> > >   >   >   >   >   >   >   Ti3t.
> > >   >   >   >   >   >   >   Let me know and I will do it.
> > >   >   >   >   >   >   >   Dimitris
> > >   >   >   >   >   >   >   --- In
> amibroker@xxxxxxxxxxxxxxx, "Herman
> > van
> > >   den
> > >   >   >   Bergen"
> > >   >   >   >   >   >   >   <psytek@xxxx> wrote:
> > >   >   >   >   >   >   >   > Hello,
> > >   >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   > 'been looking at DT's Ct formula
(nice
> > >   work!) to
> > >   >   >   predict
> > >   >   >   >   >   where
> > >   >   >   >   >   >   >   tomorrow's
> > >   >   >   >   >   >   >   > Close will touch the Ti3 - see code
> > below.
> > >   Can
> > >   >   >   anybody
> > >   >   >   >   see a
> > >   >   >   >   >   >   way to
> > >   >   >   >   >   >   >   use this
> > >   >   >   >   >   >   >   > formula to predict the Close of
> tomorrow
> > >   needed
> > >   >   to
> > >   >   >   have
> > >   >   >   >   the
> > >   >   >   >   >   Ti3
> > >   >   >   >   >   >   >   touch any
> > >   >   >   >   >   >   >   > arbitrary point? For example a
point
> on
> > >   another
> > >   >   >   >   indicator.
> > >   >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   > My math is not up to this, any help
> > would be
> > >   >   >   >   appreciated!
> > >   >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   > herman.
> > >   >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   > p=3;s=0.84;f=2/(p+1);
> > >   >   >   >   >   >   >   > // Ti3
> > >   >   >   >   >   >   >   > e1=EMA(C,p);
> > >   >   >   >   >   >   >   > e2=EMA(e1,p);
> > >   >   >   >   >   >   >   > e3=EMA(e2,p);
> > >   >   >   >   >   >   >   > e4=EMA(e3,p);
> > >   >   >   >   >   >   >   > e5=EMA(e4,p);
> > >   >   >   >   >   >   >   > e6=EMA(e5,p);
> > >   >   >   >   >   >   >   > c1=-s*s*s;
> > >   >   >   >   >   >   >   > c2=3*s*s+3*s*s*s;
> > >   >   >   >   >   >   >   > c3=-6*s*s-3*s-3*s*s*s;
> > >   >   >   >   >   >   >   > c4=1+3*s+s*s*s+3*s*s;
> > >   >   >   >   >   >   >   > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> > >   >   >   >   >   >   >   > //The value of tomorrow´s Close Ct
> that
> > >   touches
> > >   >   >   >   tomorrow´s
> > >   >   >   >   >   Ti3
> > >   >   >   >   >   >   is
> > >   >   >   >   >   >   >   > Ct=
> > >   >   >   >   >   >   >   > (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)
> *e1+
> > >   >   >   >   >   >   (c1*f^4+c2*f^3+c3*f^2+c4*f)
> > >   >   >   >   >   >   >   *e2+(c1*f
> > >   >   >   >   >   >   >   > ^3+c2*f^2+c3*f+c4*1)*e3+
> > (c1*f^2+c2*f+c3*1)
> > >   *e4+
> > >   >   >   >   (c1*f+c2*1)
> > >   >   >   >   >   >   *e5+c1*e6)/
> > >   >   >   >   >   >   >   (1-(C1*f
> > >   >   >   >   >   >   >   >
^6+C2*f^5+C3*f^4+C4*f^3)) ;//relation
> > III
> > >   >   >   >   >   >   >   > Plot(C,"Close",1,128);
> > >   >   >   >   >   >   >   > Plot(Ti3,"Ti3",4,1);
> > >   >   >   >   >   >   >   > Plot(Ct,"Ct",2,1);
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   Check AmiBroker web page at:
> > >   >   >   >   >   >   >   http://www.amibroker.com/
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >   Check group FAQ at:
> > >   >   >   >   >   >   >
> > >   >   >
> > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
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> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   >
> > >   >   >   >   >   >   > ----------------------------------------
--
> --
> > ----
> > >   ----
> > >   >   ----
> > >   >   >   ----
> > >   >   >   >   ----
> > >   >   >   >   >   ----
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> > >   >   >   >   >   > --------------------------------------------
--
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> > >   >   >   >   >   Check AmiBroker web page at:
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> > >   >   >   >   >   Check group FAQ at:
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> > >   >   >   >   > ------------------------------------------------
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> > >   >   >   Check AmiBroker web page at:
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> > >   >   >   Check group FAQ at:
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> > >   Check AmiBroker web page at:
> > >   http://www.amibroker.com/
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<*> To visit your group on the web, go to:
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