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[amibroker] Re: DT's Ct prediction for the Ti3



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Herman,
There is no answer for this general question.
Some arrays may be RevEnged [RSI, Ti3], some others not [StochD].
The next bar RSI is a function of the next bar Close Ct, the next bar 
StochD is [unfortunately] a function of Ht, Lt and Ct.
Dimitris
--- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen" 
<psytek@xxxx> wrote:
> Thank you DT, I tried this code but it requires that pb is greater 
than pa
> and also it uses C in both Ti3s. I am looking for a sulution where 
pa==pb
> and we use different price arrays.
> 
> best regards,
> herman
> 
> 
> 
> 
>   -----Original Message-----
>   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
>   Sent: Monday, October 25, 2004 1:57 AM
>   To: amibroker@xxxxxxxxxxxxxxx
>   Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> 
> 
> 
>   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
>   <psytek@xxxx> wrote:
>   > DT, I am not sure i understand the Ti3t... what i am trying to 
find
>   out is
>   > what tomorrows closing price would be to cause the crossing of 
two
>   Ti3
>   > functions.
> 
>   Herman,
>   this specific question is already in
>   http://finance.groups.yahoo.com/group/amibroker-ts/files/A%20Ti3%
>   20application/
>   "Cross(Ti3a,Ti3b) predictions.txt"
>   Dimitris
>   For example:
>   >
>   > F1 = T3( Array1, 3, 0.8 );
>   > F2 = T3( ref(Array2,-1), 3, 0.8 );
>   >
>   > Array1 and Array2 are two different arrays and could be any 
type of
>   > indicator array. For development you can plug in any of the OHLC
>   arrays, but
>   > you cannot use the same price array for both function calles.
>   > The Periods and Sensitivities are the same for both T3 function
>   calls.
>   > F2 is based on yesterdays values, F1 is based on todays values.
>   > I would like to calculate tomorrows value for Array1 that would
>   cause the
>   > two functions to cross: cross(F1, F2).
>   >
>   > Do you think this is possible?
>   >
>   > thanks for you help DT!
>   > herman
>   >   -----Original Message-----
>   >   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
>   >   Sent: Saturday, October 23, 2004 5:34 AM
>   >   To: amibroker@xxxxxxxxxxxxxxx
>   >   Subject: [amibroker] Re: DT's Ct prediction for the Ti3
>   >
>   >
>   >
>   >   Herman,
>   >   Ti3t (the next bar Ti3) is a direct function of the next bar
>   Close Ct.
>   >   Ti3t=
>   >   c1*(f*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+
>   >   (1-f)*e2)+(1-f)*e3)+(1-f)*e4)+(1-f)*e5)+(1-f)*e6)+
>   >   c2*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3)+
>   >   (1-f)*e4)+(1-f)*e5)+
>   >   c3*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3)+(1-f)*e4)+
>   >   c4*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3);
>   >   If I understand your question, you want to solve Ct for any 
given
>   >   Ti3t.
>   >   Let me know and I will do it.
>   >   Dimitris
>   >   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
>   >   <psytek@xxxx> wrote:
>   >   > Hello,
>   >   >
>   >   > 'been looking at DT's Ct formula (nice work!) to predict 
where
>   >   tomorrow's
>   >   > Close will touch the Ti3 - see code below. Can anybody see a
>   way to
>   >   use this
>   >   > formula to predict the Close of tomorrow needed to have the 
Ti3
>   >   touch any
>   >   > arbitrary point? For example a point on another indicator.
>   >   >
>   >   > My math is not up to this, any help would be appreciated!
>   >   >
>   >   > herman.
>   >   >
>   >   > p=3;s=0.84;f=2/(p+1);
>   >   > // Ti3
>   >   > e1=EMA(C,p);
>   >   > e2=EMA(e1,p);
>   >   > e3=EMA(e2,p);
>   >   > e4=EMA(e3,p);
>   >   > e5=EMA(e4,p);
>   >   > e6=EMA(e5,p);
>   >   > c1=-s*s*s;
>   >   > c2=3*s*s+3*s*s*s;
>   >   > c3=-6*s*s-3*s-3*s*s*s;
>   >   > c4=1+3*s+s*s*s+3*s*s;
>   >   > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
>   >   > //The value of tomorrow´s Close Ct that touches tomorrow´s 
Ti3
>   is
>   >   > Ct=
>   >   > (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+
>   (c1*f^4+c2*f^3+c3*f^2+c4*f)
>   >   *e2+(c1*f
>   >   > ^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+(c1*f+c2*1)
>   *e5+c1*e6)/
>   >   (1-(C1*f
>   >   > ^6+C2*f^5+C3*f^4+C4*f^3)) ;//relation III
>   >   > Plot(C,"Close",1,128);
>   >   > Plot(Ti3,"Ti3",4,1);
>   >   > Plot(Ct,"Ct",2,1);
>   >
>   >
>   >
>   >
>   >
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