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[amibroker] Re: DT's Ct prediction for the Ti3



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--- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen" 
<psytek@xxxx> wrote:
> DT, I am not sure i understand the Ti3t... what i am trying to find 
out is
> what tomorrows closing price would be to cause the crossing of two 
Ti3
> functions. 

Herman,
this specific question is already in
http://finance.groups.yahoo.com/group/amibroker-ts/files/A%20Ti3%
20application/
 "Cross(Ti3a,Ti3b) predictions.txt"
Dimitris 
For example:
> 
> F1 = T3( Array1, 3, 0.8 );
> F2 = T3( ref(Array2,-1), 3, 0.8 );
> 
> Array1 and Array2 are two different arrays and could be any type of
> indicator array. For development you can plug in any of the OHLC 
arrays, but
> you cannot use the same price array for both function calles.
> The Periods and Sensitivities are the same for both T3 function 
calls.
> F2 is based on yesterdays values, F1 is based on todays values.
> I would like to calculate tomorrows value for Array1 that would 
cause the
> two functions to cross: cross(F1, F2).
> 
> Do you think this is possible?
> 
> thanks for you help DT!
> herman
>   -----Original Message-----
>   From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
>   Sent: Saturday, October 23, 2004 5:34 AM
>   To: amibroker@xxxxxxxxxxxxxxx
>   Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> 
> 
> 
>   Herman,
>   Ti3t (the next bar Ti3) is a direct function of the next bar 
Close Ct.
>   Ti3t=
>   c1*(f*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+
>   (1-f)*e2)+(1-f)*e3)+(1-f)*e4)+(1-f)*e5)+(1-f)*e6)+
>   c2*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3)+
>   (1-f)*e4)+(1-f)*e5)+
>   c3*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3)+(1-f)*e4)+
>   c4*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+(1-f)*e3);
>   If I understand your question, you want to solve Ct for any given
>   Ti3t.
>   Let me know and I will do it.
>   Dimitris
>   --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
>   <psytek@xxxx> wrote:
>   > Hello,
>   >
>   > 'been looking at DT's Ct formula (nice work!) to predict where
>   tomorrow's
>   > Close will touch the Ti3 - see code below. Can anybody see a 
way to
>   use this
>   > formula to predict the Close of tomorrow needed to have the Ti3
>   touch any
>   > arbitrary point? For example a point on another indicator.
>   >
>   > My math is not up to this, any help would be appreciated!
>   >
>   > herman.
>   >
>   > p=3;s=0.84;f=2/(p+1);
>   > // Ti3
>   > e1=EMA(C,p);
>   > e2=EMA(e1,p);
>   > e3=EMA(e2,p);
>   > e4=EMA(e3,p);
>   > e5=EMA(e4,p);
>   > e6=EMA(e5,p);
>   > c1=-s*s*s;
>   > c2=3*s*s+3*s*s*s;
>   > c3=-6*s*s-3*s-3*s*s*s;
>   > c4=1+3*s+s*s*s+3*s*s;
>   > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
>   > //The value of tomorrow´s Close Ct that touches tomorrow´s Ti3 
is
>   > Ct=
>   > (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+
(c1*f^4+c2*f^3+c3*f^2+c4*f)
>   *e2+(c1*f
>   > ^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+(c1*f+c2*1)
*e5+c1*e6)/
>   (1-(C1*f
>   > ^6+C2*f^5+C3*f^4+C4*f^3)) ;//relation III
>   > Plot(C,"Close",1,128);
>   > Plot(Ti3,"Ti3",4,1);
>   > Plot(Ct,"Ct",2,1);
> 
> 
> 
> 
> 
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>   http://www.amibroker.com/
> 
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> 
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