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To check what you want, try H>sum(HHV(H,period),period); I have not tried
this myself, use at your own risk. Ron D
----- Original Message -----
From: "mrdavis9" <mrdavis9@xxxxxxxxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Thursday, July 01, 2004 10:00 AM
Subject: Re: [amibroker] Newbie needs help with HHV
> This is a logic problem. The High can never be higher than itself. This
> will find the bar where the High is equal to the Highest high.
> H==HHV(H,period);
>
>
>
>
> ----- Original Message -----
> From: "nsundby" <nick@xxxxxxxxxxxxxxxxxxxx>
> To: <amibroker@xxxxxxxxxxxxxxx>
> Sent: Thursday, July 01, 2004 9:03 AM
> Subject: [amibroker] Newbie needs help with HHV
>
>
> > HI,
> >
> > I want to test if the current bar has a higher high than the highs of
> > the preceding n bars. However HHV includes the current bar, so
> > testing if H>HHV(H,period) doesn't work.
> >
> > How should I do it?
> >
> > Many thanks
> > Nick
> >
> >
> >
> >
> > Check AmiBroker web page at:
> > http://www.amibroker.com/
> >
> > Check group FAQ at:
> http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > Yahoo! Groups Links
> >
> >
> >
> >
> >
>
>
>
>
> Check AmiBroker web page at:
> http://www.amibroker.com/
>
> Check group FAQ at:
http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> Yahoo! Groups Links
>
>
>
>
>
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