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Rick,
>if there is an interdependency between 2
> arrays, that is each relies on the other, you would have to use for-
> loops to set their values properly?
General answer is YES, but in that case you can write the code
for alternate buys in single line using modulo operator
Buy = ( BarIndex() % 2 ) == 1;
Sell = Ref( Buy, -1 );
Best regards,
Tomasz Janeczko
amibroker.com
----- Original Message -----
From: "Rick Charon" <rickcharon@xxxxxxxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Friday, May 07, 2004 9:15 PM
Subject: [amibroker] Re: Improper code behavior
> Thank you Graham and Tomasz,
> The idea of the array shifting all at once explains my dificculty. In
> general, does this mean that if there is an interdependency between 2
> arrays, that is each relies on the other, you would have to use for-
> loops to set their values properly? Tomasz, I did read the docs you
> suggested. Any other pointers are greatly appreciated!
> Rick
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" <amibroker@xxxx>
> wrote:
> > Graham is perfectly correct.
> >
> > Rick - you should read:
> > http://www.amibroker.com/guide/h_understandafl.html
> >
> > Ref shifts entire array at once instead of accessing since array
> elements.
> >
> > Best regards,
> > Tomasz Janeczko
> > amibroker.com
> > ----- Original Message -----
> > From: "Graham" <gkavanagh@xxxx>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Friday, May 07, 2004 3:50 AM
> > Subject: RE: [amibroker] Improper code behavior
> >
> >
> > > Not certain what you are trying to do, but just looking at your
> code
> > > Posopen is 0 to start with, then you assign buy==1 when previous
> posopen is
> > > 0. ie buy=1 at second bar. You then tell it that posopen = buy
> which was
> > > last determined to be 1, but buy is held back by the original
> > > ref(posopen,-1) which was 0. Unless you have another condition to
> break the
> > > original buy statement it will always stay at buy1 as you kept
> posopen at 0.
> > > I think you would be better with a loop for this
> > > posOpen[0] = 0;
> > > for(i=1;i<BarCount;i++)
> > > { if(posopen[i-1]==0)
> > > { Buy[i]=1; posOpen[i]=1;}
> > > else
> > > { Buy[i]=0; posOpen[i]=0;}
> > > }
> > > Sell = 0;
> > > Filter=1;
> > > AddColumn(BarIndex(), "BarIndex");
> > > AddColumn(posOpen, "posOpen");
> > > AddColumn(Ref(posOpen, -1), "Ref(posOpen -1)");
> > > AddColumn(Sell, "sell");
> > > AddColumn(Buy, "buy");
> > >
> > > This will give alternating buy values of 0 and 1
> > >
> > > But there is another easier way of doing this if you are trying
> to determine
> > > if you have an open trade. I just used the buy and sell
> conditions of
> > > barindex as a means to test it.
> > >
> > > Buy = BarIndex()==BarCount-10;//buy conditions
> > > Sell = BarIndex()==BarCount-5;//sell conditions
> > > Buy = Flip(Buy,Sell);//holds buy=1 until sell signal
> > >
> > > Filter=1;
> > > AddColumn(Buy,"B",1);
> > > AddColumn(Sell,"S",1);
> > >
> > > Hope this is some help, as it was hard to determine what you were
> intending
> > > to do.
> > >
> > > Cheers,
> > > Graham
> > > http://e-wire.net.au/~eb_kavan/
> > >
> > > -----Original Message-----
> > > From: Rick Charon [mailto:rickcharon@x...]
> > > Sent: Friday, May 07, 2004 9:15 AM
> > > To: amibroker@xxxxxxxxxxxxxxx
> > > Subject: [amibroker] Improper code behavior
> > >
> > > The following code doesn't work as expected. What am I missing?
> > > Thanks. (The buy flips once, then stays 1, even though Ref
> (posOpen, -
> > > 1) is 1.
> > >
> > > Filter = 1;
> > >
> > > posOpen[0] = 0;
> > >
> > > Buy = (Ref(posOpen, -1) == 0);
> > >
> > > posOpen = Buy;
> > >
> > > Sell = 0;
> > >
> > > AddColumn(BarIndex(), "BarIndex");
> > >
> > > AddColumn(posOpen, "posOpen");
> > >
> > > AddColumn(Ref(posOpen, -1), "Ref(posOpen -1)");
> > >
> > > AddColumn(Sell, "sell");
> > >
> > > AddColumn(Buy, "buy");
> > >
> > >
> > >
> > >
> > >
> > >
> > >
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