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If you have 5 different MAs [17, 35, 49, 112 and 238 bars] you should
compare the distances with
min(d1,min(d2,min(d3,min(d4,d5)))).
The second question is more interesting, you can use loops to find
the closest MA.
If you search various MAs from na to nb, then the closest MA makes
the abs(C-MA(C,n)) minimum.
na=10;nb=100;step=1;
f=LastValue(abs(C-MA(C,na)));
for(n=na;n<=nb;n=n+step)
{
//Plot(MA(C,n),"",colorLightGrey,1);
d=LastValue(abs(C-MA(C,n)));
if(d<f)
{
n1=n;
f=d;
}
}
Plot(C,"\nC",1,8);
Plot(MA(C,n1),"MA(C,"+WriteVal(n1,1.0)+")",colorDarkRed,8);
Uncomment the //Plot... line to see the rest MAs.
Calibrate the na, nb, step according to your research field.
Dimitris Tsokakis
--- In amibroker@xxxxxxxxxxxxxxx, "mmqp" <mmqp@xxxx> wrote:
> Hi, I have 5 different moving average. I'd like to know/measure
the
> least distance of last close to these average. Another word is
> which moving average is closest to today close. I understand that
> this can be done in a brute force way however I would like to know
> if there is a better mathematical way to do this in case of more
> than 5 moving average. TIA.
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