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as Dimitri, I create wl3 with 2
tickers, the ^DJI and the ^DJI with the last 5 bars removed ( called test and
attached)
use the code below ( provided by you)
and see ( if I plot the ticker with
longest history)
<IMG alt="" hspace=0 src="jpg00020.jpg"
align=baseline border=0>
<FONT color=#008000
size=1>
//Count tickers in watchlist function
WatchlistNumber=3<FONT
size=1>;
function CountTickersInWatchList(
Listnum )
{
// retrive comma-separated list of symbols in watch list <FONT
size=1>
list = GetCategorySymbols<FONT
size=1>( categoryWatchlist, listnum );
Counter=0; <FONT
color=#008000 size=1>// INITIALIZE COUNTER <FONT
size=1>
for( i = <FONT color=#ff00ff
size=1>0; ( sym = <FONT color=#0000ff
size=1>StrExtract( list, i ) ) != <FONT
color=#ff00ff size=1>""; i++ )
{
// TO COUNT BAR BY BAR YOU HAVE TO USE ARRAYS NOT SCALAR AND USE FOREIGN TO
FIND OUT HOLES
Counter=Counter + ( NOT <FONT color=#0000ff
size=1>IsNull( <FONT color=#0000ff
size=1>Foreign( sym, <FONT color=#ff00ff
size=1>"C", False ) ) );
}
return Counter;
}
Plot(<FONT color=#0000ff
size=1>Foreign(<FONT color=#ff00ff
size=1>"~count",<FONT color=#ff00ff
size=1>"v"),<FONT color=#ff00ff
size=1>"<FONT face="Courier New" color=#ff00ff
size=1>Composite"<FONT color=#000000
size=1>,colorRed,1<FONT
size=1>);
Plot(CountTickersInWatchList(
WatchlistNumber) ,"<FONT
face="Courier New" color=#ff00ff size=1>Foreign fixup false<FONT
color=#ff00ff size=1>",<FONT
face="Courier New" size=1>colorGreen<FONT color=#000000
size=1>,1<FONT
color=#000000>);
GraphXSpace=2<FONT
size=1>;
<BLOCKQUOTE
>
----- Original Message -----
<DIV
>From:
Dimitris
Tsokakis
To: <A title=amibroker@xxxxxxxxxxxxxxx
href="">amibroker@xxxxxxxxxxxxxxx
Sent: Saturday, February 28, 2004 3:33
PM
Subject: [amibroker] Re: Re: empty scan
of a watchlist (?)
Tomasz,
Do not doubt I read very carefully your
<FONT
size=2>http://groups.yahoo.com/group/amibroker/message/59548<FONT
size=2>?
You wrote
"According to my understanding the question was how to get
the same resultas you would get from AddToComposite, i.e. the number of
components on BAR BY BAR basis (exactly like ATC will do
that)"
As it is obvious from the att. gif, the results are not the
same.
The ATC solution falls from 3 to 2 for the last 5 bars, as
it should be
[I repeat, I deleted the last 5 AAPL
quotations]
Your code gives an unexpected ziggy result. The population
of WL20 is 2 or 3 bar by bar !!
Do you see it OK ?
Dimitris TsokakisSend BUG
REPORTS to bugs@xxxxxxxxxxxxxSend SUGGESTIONS to
suggest@xxxxxxxxxxxxx-----------------------------------------Post
AmiQuote-related messages ONLY to: amiquote@xxxxxxxxxxxxxxx (Web page: <A
href="">http://groups.yahoo.com/group/amiquote/messages/)--------------------------------------------Check
group FAQ at: <A
href="">http://groups.yahoo.com/group/amibroker/files/groupfaq.html
__________
NOD32 1.637 (20040228) Information __________This message was checked
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href="">http://www.nod32.com
Attachment:
Attachment:
Description: "Description: Zip compressed data"
Attachment:
Description: "Test.zip"
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