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I recall some added rider to using Barcount when it was introduced, I think
you had to turn off QuickAFL for Indicators in the preferences, but I am not
absolutely certain of this.
>From the Help files
BarCount constant gives the number of bars in array (such as Close, High,
Low, Open, Volume, etc). Array elements are numbered from 0 (zero) to
BarCount-1.
To get the first bar you can use array[ 0 ], to get the last bar of array
you can use array[ BarCount - 1 ];
For example:
Close[ 5 ];
Represents the sixth element (bar) of the close array.
Close[ 0 ];
Represents the very first available bar of the close array.
High[ BarCount - 1 ];
Represents the last bar of High array.
This example illustrates the for statement:
myema[ 0 ] = Close[ 0 ];
for( i = 1; i < BarCount; i++ )
{
myema[ i ] = 0.1 * Close[ i ] + 0.9 * myema[ i - 1 ];
}
Cheers,
Graham
http://groups.msn.com/ASXShareTrading
http://groups.msn.com/FMSAustralia
-----Original Message-----
From: Ed [mailto:pablito@xxxxxxx]
Sent: Saturday, 25 October 2003 5:16 PM
To: amibroker@xxxxxxxxxxxxxxx
Subject: Re: [amibroker] size of an array in AFL?
to my knowledge:
LastValue(BarIndex()): gives the number of bars available for the symbol
BarIndex(): gives the bar number counting from the first bar available for
the symbol.
I'm a bit confused about BarCount though. I always thought that BarCount:
gives the number of bars inside an indicator window. So the first bar shown
inside the window is bar-number 0.
However, I put inside the indicator builder:
WriteVal(BarCount);
WriteVal(LastValue(BarIndex());
WriteVal(BarIndex());
The last 2 do as expected. WriteVal(LastValue(BarIndex()); always gives you
the total number of bars available for a symbol. WriteVal(BarIndex()); gives
you the index of the bar and its output changes when you move the cursor
with the amount of bars you move the cursor back.
However BarCount behaves differently. Actually if a symbol has 2900 bars
WriteVal(BarCount); prints 2900 if you put the cursor on any bar if you show
ALL data in the chart. If I put only 2 bars in a chart WriteVal(BarCount);
prints 52 when I put the curson on the second and last bar.
I played with it a little but did not find out yet exactly how BarCount is
defined.
Maybe somebody can enlighten me?
Thanks, Ed
----- Original Message -----
From: Dave Merrill
To: amibroker@xxxxxxxxxxxxxxx
Sent: Saturday, October 25, 2003 10:01 AM
Subject: RE: [amibroker] size of an array in AFL?
in most languages, it's possible to find out the size of an array directly,
by examining some property of the array itself or applying some function to
it, without having to know how it was created. some examples are:
array.length
array.size
SizeOfArray(array)
is that possible in AFL? if not, it can be worked around since we do in
general know how every array was created, but it's less elegant and less
self contained.
dave
I'm not sure how to answer this because it depends on which array you are
refering too.
Are you refering to a stock data array of some description? If so you could
use the Barcount constant which will return the number of bars in the array.
Remember it's zero based so the last bar is refered to as: Barcount - 1
Regards,
William Peters
www.amitools.com
-----Original Message-----
From: Dave Merrill [mailto:dmerrill@xxxxxxx]
sorry for the dumb question, but what's the syntax for getting the size
(number of elements) in an array? I want to do something like this, only
that works:
for(i=1; i<=array.length; i++) {
thanks,
dave
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