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Yes can follow the principle of the problem, and as you said there can be
many points that define the second point backwards. It would be my
preference to find the 3rd previous one (P3) and check if the intervening
point P2 is within reasonable proximity to the line between P1 and P3. This
would give confirmation that P3 could be correct.
The further problem would be whether P1 is correct, if not then the exercise
is incorrect. Then you would go by iterative process backwards using P2, P3
etc as your first point and try to locate previous points to confirm a trend
line that is indicative of the price action.
Cheers,
Graham
http://groups.msn.com/ASXShareTrading
http://groups.msn.com/FMSAustralia
-----Original Message-----
From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@xxxxxxxxx]
Sent: Thursday, 11 September 2003 2:08 PM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Subject: Re: TJ - Solution please
According to the last epi description, he detects first the p1 [the
most recent p1] and then searches into the past for a p2.
Of course, there are many p2s before p1 and he should choose which
one he prefers [I would suggest the closest to p1, but ...]
As we have in zig function the last leg variable, in epi´s project we
have the last pair [p1,p2] variable or, to be more specific, the last
[p1,(p2A, p2B, p2C,...)] variable.
We can do something from the code part, but it would be better to
specify the selection of p2, in order not to be lost in the chaos. Except
epi´s special request, the subject [simultaneous definition of
pairs of points with different properties] is interesting.
Zig is a simple example, it links Peaks and Troughs [but with the
same per coefficient]
Dimitris Tsokakis
--- In amibroker@xxxxxxxxxxxxxxx, "Graham" <gkavanagh@xxxx> wrote:
> DT you are making my head spin decyphering that one :)
>
> Cheers,
> Graham
> http://groups.msn.com/ASXShareTrading
> http://groups.msn.com/FMSAustralia
>
>
> -----Original Message-----
> From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> Sent: Thursday, 11 September 2003 1:50 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Subject: Re: TJ - Solution please
>
>
> As you see, it is better to describe your exact preference first
and
> then try the exact code [if any].
> You should know something in advance : The p2 is known to be a p2
as
> soon as p1 is recognised as p1 !!
> You will have, for example, the last 10 candles neutral and then,
> with the new data import, all of a sudden, yesterday will become a
p1
> and 6 bars ago will become a p2!!
> You define the properties of the past, when you detect a p1 and
this
> is done in reverse time order.
> In other words, the event p1 looks into the future by one bar, but
> the event p2 looks into the future by many bars.
> Among the others, think the alternative, to define first p2 and
then
> expect a lower peak p1. This detection would look into the future
by
> only one day , which is not bad at all.
> The decision is yours, of course...
> Dimitris Tsokakis
> --- In amibroker@xxxxxxxxxxxxxxx, "epintoem" <epintoem@xxxx> wrote:
> > Thanks for this... We are close but not quite.
> >
> > Every peak will have a peak that is higher than it. so we might
> have
> > a situation where a higher peak might be the point for two peaks
> > subsequent peaks that are lower.
> >
> > Assume p1 is the the most recent peak at 10.50 on 9./04
> >
> > p2 could be a peak with a value of 10.00 on 8/26
> >
> > P3 could be the peak with a value of 13.00 on 7/25 that would
> connect
> > to both p1 and P2
> >
> > Thanks so much for your help
> >
> >
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "Dimitris Tsokakis"
> <TSOKAKIS@xxxx>
> > wrote:
> > > Here is my definition of a peak
> > > High greater than high previous day and following day. Most
> recent
> > > high greater than close two days earlier.
> > >
> > >
> > > condP=Ref(H,-1)>Ref(H,-2) AND Ref(H,-1)>H AND Ref(H,-1)>Ref(C,-
3);
> > >
> > > The conditions for the peak prior to this one are the same
except
> > > that the high should be greater than the peak it is connecting
to.
> > >
> > > It was Dimitris who provided me the code for IB.
> > >
> > > Hope this helps
> > >
> > > ********************************************************
> > >
> > > If I understand well, you search for pairs P1, P2.
> > > The green candles are all the CONDP occurrences.
> > > The red triangles P1 have the previous peak higher.
> > > The blue triangles have the next peak lower.
> > > The rest green candles are of no interest.
> > > Do you want now to link P2, P1 pair with a line, like the dotted
> > black line of the gif ?
> > > Or you want a zig line connecting cascade P1,P2,P1,P2,... ?
Please
> > > advise.
> > >
> > > CONDP=Ref(H,-1)>Ref(H,-2) AND Ref(H,-1)>H AND Ref(H,-1)>Ref(C,-
3);
> > > P11=Ref(CONDP,1); H1=ValueWhen(P11,H,1); H2=ValueWhen(P11,H,2);
> > > H0=ValueWhen(P11,H,0);
> > > P1=P11 AND H2>H1;
> > > P2=P11 AND H1>H0;
> > > PlotShapes(shapeUpTriangle*P1,colorRed);
> > > PlotShapes(shapeDownTriangle*P2,colorBlue);
> > > Plot(C,"",p11*colorYellow+1,64);
> > >
> > > Please advise.
> > > Dimitris Tsokakis
>
>
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