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for simplicity sake I am taking your indicator to be rsi
x=rsi(14)==hhv(rsi(14),60);
see if that works
--- In amibroker@xxxxxxxxxxxxxxx, "Jayson" <jcasavant@xxxx> wrote:
> Ron,
> when you run your scan choose to look only at the last day (n=1) of
data.
> This will return only those stocks meeting your criteria as of the
last
> bar...... So filter=hhv(h,4) when run on an exploration range of
n=1 will
> return only stocks who meet the criteria of being the highest high
value of
> high for the last 4 days on your last bar
>
> Regards,
> Jayson
> -----Original Message-----
> From: mrdavis9 [mailto:mrdavis9@x...]
> Sent: Saturday, July 26, 2003 1:13 AM
> To: dave cogburn; amibrokeryahoogroups
> Cc: jeff davis
> Subject: [amibroker] HHV OF an indicator
>
>
> epintom said>>Condh=mycondition;
> how can I get the highest close of the
4 days
> preceeding my
> condition
>
>
> William Peters said>> Is this what your after. The Close Price is
the
> highest it has been for the previous 4 bars
>
> Filter = LastValue( Ref( HHV( Close, 4 ), -1 ) ) < Close;
> AddColumn( Close, "Close " );
> AddColumn( Open, "Open " );
> AddColumn( High, "High " );
> AddColumn( Low, "Low " );
> AddColumn( Volume, "Volume " );
> Regards,
> William Peters
>
>
> DT said>>William,
> epi asks the HHV(C,4)"preceeding his condition"
> You obviously calculate something conditionless.
> DT
>
>
> I want to create a scan that finds only those stocks where the
highest
> value of an indicator that has occurred within in the past 60 days
is
> actually occurring on the very day that I am running the scan.
This is my
> first attempt at using HHV in a scan. I also want to run LLV scans
in the
> same way. I studied a lot of these posts regarding HHV and LLV,
but was
> not able to make such a scan.
> I learn new things best by having a working scan that does what I
want.
> Then by fine tuning it, I grow to understand it better.
> All responses will be appreciated. Ron D
>
>
>
>
>
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