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[amibroker] Re: RE RSI



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Yes, see where rsi(14) finds support/ressistence and use
that value instead of 39.82 which was specific for the
example. Then u will see how the graph acts as support in the
future. TJ put 39.82 in the param function so u can adjust this
easily.
nand


--- In amibroker@xxxxxxxxxxxxxxx, "Jayson" <jcasavant@xxxx> wrote:
> Could you elaborate on how you use this indicator........I did not 
see the
> article but it appears you set the stall value at a significant 
turn of the
> RSI ??
> 
> Regards,
> Jayson
> -----Original Message-----
> From: quchi [mailto:adrian@x...]
> Sent: Tuesday, May 27, 2003 12:18 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: RE RSI
> 
> 
> Hi
> what's a 'stall" value?
> I think that - as I remeber -TASC is been out for a while now -
> that 39.82 is particular to the example in the article
> Anyway THIS is a incredible cool indicator and I'm using it since 
the
> day TASC was out - I had something similar before but this is MUCH
> better(of course done by TJ:) - thx TJ and Dr Giorgos Siligardos
> wow
> 
> 
> --- In amibroker@xxxxxxxxxxxxxxx, "nkis22" <nkishor@xxxx> wrote:
> > The 39.82 is the stall value of RSI(14).
> > nand
> >
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
> <TSOKAKIS@xxxx>
> > wrote:
> > > Tomasz,
> > > There is something I did not understand in your TASC RE RSI
> formula:
> > > The text is :"The reverse-engineered RSI, or RevEngRSI for 
short,
> > can
> > > help determine the following time period's closing price using
> the
> > > value of the oscillator. "
> > > If I put value=LastValue(RSI()) [the 39.82 in your formula] ,
> then,
> > > obviously, LastValue(RevEngRSI) will be equal to the [known]
> > LastValue
> > > (C).
> > > Where is the "following time periods closing price" ?[ie the
> > unknown
> > > tomorrows close]
> > > In general, since [todays] RSI() is a function of [todays] 
Close,
> > the
> > > reverse function would give [todays] Close as a function of
> > [todays]
> > > RSI().
> > > But, todays Close is known and doesnt need RSI() to be 
calculated.
> > > The whole procedure seems meaningless to me. Do I miss 
something ?
> > > TIA
> > > Dimitris Tsokakis
> 
> 
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