[amibroker] Re: How to solve in AFL.....

["Keith Bennett" <kbennett@xxxxxxxxxx>]

Thanks to all for comments, and to Tomasz for (as always) the simple 
solution.

x = AMA(C,C > Ref(C,-1)); // Works great.

Keith


--- In amibroker@xxxxxxxxxxxxxxx, uenal.mutlu@xxxx wrote:
> Dimitris,
> 
> From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
> >
> 
> > Tomasz,
> > Let us look at the question first :
> > Your code is [I suppose] for the question
> > x = IIF(Condition is TRUE, a * b, Ref(x,-1));
> > Keith question was
> > x = IIF(Condition is TRUE, a * b,
> >      IIF(Condition is FALSE, Ref(x,-1),NULL));
> > I think it does not make sense because Condition is TRUE OR FALSE 
> > without 3rd possibility
> 
> yes, and especially if it is the same condition for the same bar :-)
> 
> 
> > DT
> > 
> > 
> > --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" 
<amibroker@xxxx> 
> > wrote:
> > > Hello,
> > > 
> > > Using AMA/AMA2:
> > > 
> > > x = AMA( a * b, Condition == True );
> > > 
> > > Using loops:
> > > 
> > > for( i = 1; i < BarCount; i++ )
> > > {
> > >    if( Condition[ i ] )
> > >    {
> > >     x[ i ] = a * b;
> > >    }
> > >    else
> > >    {
> > >     x[ i ] = x[ i - 1 ];
> > >   }
> > > }
> > >  
> > > 
> > > Best regards,
> > > Tomasz Janeczko
> > > amibroker.com
> > > ----- Original Message ----- 
> > > From: "Keith Bennett" <kbennett@xxxx>
> > > To: <amibroker@xxxxxxxxxxxxxxx>
> > > Sent: Thursday, May 08, 2003 12:33 PM
> > > Subject: [amibroker] How to solve in AFL.....
> > > 
> > > 
> > > > 
> > > > Hi,
> > > > 
> > > > The following situation frequently occurs, but it doesn't 
seem 
> > > > possible to solve directly due to the self reference.
> > > > 
> > > > How do you tackle this in AFL:
> > > > 
> > > > x = IIF(Condition is TRUE, a * b,
> > > >     IIF(Condition is FALSE, Ref(x,-1),NULL));
> > > > 
> > > > Thanks
> > > > Keith


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