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forget for a moment the formula [which may be wrong] and examine the
logic :
day1
COND=TRUE
X=a*b
day2
COND=FALSE
X should be its previous value, ie a*b again
day3
COND=FALSE
X should be its previous value, ie a*b again
...
After the first TRUE condition, all next values will be a*b
DT
--- In amibroker@xxxxxxxxxxxxxxx, "Graham" <gkavanagh@xxxx> wrote:
> Unless you have 2 days running of false. I have found that then it
does not
> always take the previous value which was already a reverted result.
>
> Cheers,
> Graham
> http://groups.msn.com/ASXShareTrading
> http://groups.msn.com/FMSAustralia
>
> -----Original Message-----
> From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> Sent: Thursday, 8 May 2003 7:44 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: How to solve in AFL.....
>
> Your x, as described, is always a*b. Suppose day1 with true
> condition, then
> day1
> COND=TRUE
> X=a*b
> day2
> COND=FALSE
> X should be its previous value, ie a*b again
> Agree?
> DT
> --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
<TSOKAKIS@xxxx>
> wrote:
> > As it is written, Condition may be TRUE, FALSE or something else ?
> > DT
> > --- In amibroker@xxxxxxxxxxxxxxx, "Keith Bennett" <kbennett@xxxx>
> > wrote:
> > >
> > > Hi,
> > >
> > > The following situation frequently occurs, but it doesn't seem
> > > possible to solve directly due to the self reference.
> > >
> > > How do you tackle this in AFL:
> > >
> > > x = IIF(Condition is TRUE, a * b,
> > > IIF(Condition is FALSE, Ref(x,-1),NULL));
> > >
> > > Thanks
> > > Keith
>
>
>
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