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Your x, as described, is always a*b. Suppose day1 with true
condition, then
day1
COND=TRUE
X=a*b
day2
COND=FALSE
X should be its previous value, ie a*b again
Agree?
DT
--- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
wrote:
> As it is written, Condition may be TRUE, FALSE or something else ?
> DT
> --- In amibroker@xxxxxxxxxxxxxxx, "Keith Bennett" <kbennett@xxxx>
> wrote:
> >
> > Hi,
> >
> > The following situation frequently occurs, but it doesn't seem
> > possible to solve directly due to the self reference.
> >
> > How do you tackle this in AFL:
> >
> > x = IIF(Condition is TRUE, a * b,
> > IIF(Condition is FALSE, Ref(x,-1),NULL));
> >
> > Thanks
> > Keith
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