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The case may have been trivial - but the response wasn't
Thanks
--- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" <amibroker@xxxx>
wrote:
> Ricko,
>
> In fact there is rarely need to use for-loop
> especially in such trivial cases as your describe.
>
> Condition = High < MA( High, 9 );
> Filter = Sum( Condition, 5 ) == 5; // condition has to be met each
bar for last 5 bars.
>
> Best regards,
> Tomasz Janeczko
> amibroker.com
> ----- Original Message -----
> From: "ricko8294_98" <ricko@xxxx>
> To: <amibroker@xxxxxxxxxxxxxxx>
> Sent: Friday, April 18, 2003 7:58 PM
> Subject: [amibroker] Re: if then else
>
>
> > Struggling with this code.
> > If I wanted to find a stock where for each of the past 5 days,
the
> > high was lower than the previous 9 day moving average, how would
I
> > code that? I can't seem to make the code work using the Ref(h,-
[i])
> > bit
> >
> > Thanks
> > --- In amibroker@xxxxxxxxxxxxxxx, "amiabilityy"
<amiabilityy@xxxx>
> > wrote:
> > > Hi
> > >
> > > This seems to work, I assume you only wanted this as a simple
test
> > > to figure out how to use if then else.
> > >
> > >
> > > Aa=DayOfWeek();
> > > for( i = 0; i < BarCount; i++ )
> > >
> > > {
> > > if ( Aa[ i ]==1)
> > > bb[ i ] = 1000;
> > > else
> > > bb[ i ] = 0;
> > > }
> > >
> > >
> > > Buy=Filter=1;
> > > AddColumn(Aa,"datenumber");
> > > AddColumn(bb,"mydate");
> > >
> > >
> > > The value of 1000 is just to make it more obvious, for
testing
> > when
> > > running an exploration.
> > >
> > >
> > >
> > > Peter.
> > >
> > > --- In amibroker@xxxxxxxxxxxxxxx, "kk12338" <kk2628@xxxx> wrote:
> > > > Hi,
> > > >
> > > > The following code still return 1 to tday irregardless
DayofWeek
> > > cud
> > > > be 2 or 3 or 4 or 5, is my coding wrong ?
> > > >
> > > > if (dayofweek()==1)
> > > > tday=1;
> > > > else
> > > > tday=0;
> > > >
> > > > Thanks
> > > > KK
> >
> >
> >
> > Send BUG REPORTS to bugs@xxxx
> > Send SUGGESTIONS to suggest@xxxx
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> >
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> >
> >
> >
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