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Stephane
I am probably just mis-communicating, The first part of the equation
(5-1) should always be the opposite way(1-5) or (recent price - less
recent price) and that would always establish if the slope is
positive or negative depending on if price were rising or falling,
then it would alway be divided by the period(20-2) or abs(2-20) which
would always be a positive #.
Hope that makes more sense
wdbaker
--- In amibroker@xxxx, "Stephane Carrasset" <nenapacwanfr@xxxx> wrote:
> suppose 20 days ago the close is 5$
> and 2 days ago the close is 1$
>
> the slope of the price must be negative 1$ is less than 5$
> BUT
> (5-1)/ (20-2) is positive
>
>
> Stephane,
> > I have less than a highschool education so that could be getting
in
> > the way but I think that the first part of the equation
determines
> if
> > the slope is positive or negative, the last part of the equation
> just
> > establishes the period to divide by to get the slope. I just
> > recently began studying this though so could be wrong.
> >
> > Thanks
> > wdbaker
> > --- In amibroker@xxxx, "Stephane Carrasset" <nenapacwanfr@xxxx>
> wrote:
> > >
> > >
> > > > the w & y issue, I think the equation goes slope=(endval-
> > startval)/
> > > > (time or bars) and the way you have it written would give me
a
> > > > negative # of bars I think.
> > >
> > > yes, negative and
> > > if endval-startval is positive ( startval< endval)the slope is
> > > negative and
> > > if endval-startval is negative( startval>endval) the slope is
> > positive
> > >
> > > why do you want that the slope is always positive??
> > >
> > > stephane
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