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Re: Count function?



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The "~COUNT" artificial ticker has nothing to do with a COUNT() 
function.
See in AA the results of
x=Count();
y=Cum(1);
Filter=1;
AddColumn(x,"");AddColumn(y,"");
DT
--- In amibroker@xxxx, "nirvana1x" <nirvanaiam@xxxx> wrote:
> are you sure it said count as it may be from a script or dll.
> similar to the count in the formula below. but you said in blue 
> whereee as the count here is in red.
> 
> 
> 
> /*Continuation of a DOWNTREND*/
> K=EMA((H+L+C)/3,10);
> S1=200*(K-Ref(K,-1))/(K+Ref(K,-1));
> rs=EMA(EMA(S1,3),3);
> s3= Ref(RS,-1)==HHV(RS,5) AND abs(Ref(RS,-1))<=0.5 ; 
> values18 = s3>0;
> AddToComposite(Values18,"~continuationdown","V");
> /*Continuation of an UPTREND*/
> K=EMA((H+L+C)/3,10);
> S1=2*(K-Ref(K,-1))/(K+Ref(K,-1));
> rrs=100*EMA(S1,3);
> rs=EMA(rrs,3);
> s3= Ref(RS,-1)==LLV(RS,5) AND abs(Ref(RS,-1))<0.5 ; 
> values19 = s3>0;
> AddToComposite(Values19,"~continuationup","V");
> /*Population of the group*/
> AddToComposite(1,"~count","V");
> Buy=0;
> Plot(100*Foreign("~continuationup","V")/Foreign
> ("~count","V"),"Up",5,1);
> Plot(100*Foreign("~continuationdown","V")/Foreign
> ("~count","V"),"Down",4,1);
> Title=" UP="+WriteVal(100*Foreign("~continuationup","V")/Foreign
> ("~count","V"),1.2)+
> ", UP THE LAST 3 DAYS="+
> WriteVal(Sum(100*Foreign("~continuationup","V")/Foreign
> ("~count","V"),3),1.2)+
> ", DOWN="+WriteVal(100*Foreign("~continuationdown","V")/Foreign
> ("~count","V"),1.2)+
> ",DOWN THE LAST 3 DAYS="+
> WriteVal(Sum(100*Foreign("~continuationdown","V")/Foreign
> ("~count","V"),3),1.2);
> 
> 
> cheers: john.
> 
> 
> --- In amibroker@xxxx, "Rick Parsons" <RickParsons@xxxx> wrote:
> > Use addcolumn and see what it contains. Might provide a clue.
> > 
> > Rick
> > -----Original Message-----
> > From: Owen Davies [mailto:owen5819@x...]
> > Sent: Monday, June 24, 2002 6:55 PM
> > To: amibroker@xxxx
> > Subject: [amibroker] Count function?
> > 
> > 
> > I was just playing with the Indicator Builder and happened
> > to name a variable "Count." It appeared in blue, so I assume
> > there is a Count function, which seems to be undocumented.
> > Can anyone supply info about it?
> > 
> > Owen
> > 
> > 
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