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Re: [amibroker] Re: Fw: RS Peaks,II



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Hello Dimitris,

I am going to fix these functions to allow negative values.

Best regards,
Tomasz Janeczko
===============
AmiBroker - the comprehensive share manager.
http://www.amibroker.com


----- Original Message -----
From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Tuesday, August 21, 2001 8:43 PM
Subject: [amibroker] Re: Fw: RS Peaks,II


Thank you Tomasz, I īll follow RS1=RS+10;
Joining two divergences looks promissing.
I will revert with the code.
If it is technically possible, it would be better in the future to
have also negative peak and trough values for all these functions
(ROC, %R, RS etc) vibrating around zero.
The use of abs is not useful here.
Divergence is the same for A and A+10, but other quantities like
% do not permit such transformation.
Thanks again for explanation.
Dimitris Tsokakis
--- In amibroker@xxxx, "Tomasz Janeczko" <amibroker@xxxx> wrote:
> Hello Dimitris,
>
> Currently Zig, Peak, Trough functions work correctly with positive
numbers only.
>
> Best regards,
> Tomasz Janeczko
> ===============
> AmiBroker - the comprehensive share manager.
> http://www.amibroker.com
>
> ----- Original Message -----
> From: Dimitris Tsokakis
> To: amibroker@xxxx
> Sent: Tuesday, August 21, 2001 4:00 PM
> Subject: [amibroker] Fw: RS Peaks,II
>
>
> Dear Tomasz,
> I see that the wrong values appear when RS<0.
> Does function PEAK accept as Array negative numbers ?
> (Level at A is the first negative value for RS and it holds this
> value until next positive RS.)
> Although something different happens in the middle of the chart.
> PEAK graph seems to follow negative values, but not always.
> Confused.
>
> Best Regards
> Dimitris Tsokakis
> P. S. 1. The value of crosshair is more than obvious here.
> I should draw an horizontal line to see that level A was not a
> previous peak. The only problem is the colour. With blue
> background is not easily visible.
> Anyway, it is a great help.
> P. S. 2. If there is no other hint and since -10<RS<10 in the
> majority of cases, I will transform RS to RS1 with
> RS1=10+RS, where everything goes fine.
>
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