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Hi Dimitris,
Thanks very much for your help.
Yes you are right.
In fact I'm trying to adapt some idea coming from a
very interesting book called "Trading Systems that Work" from Tomas
Stridsman.
But everything is in EasyLanguage which with I am
not familiar. I have downloaded a free help of this language and now I try to
build some given exploration in AFL.
The original formula is
Prof = 1 + PositionProfit(1) / EntryPrice(1) *
BigPointValue;
CumProf = CumProf * Prof;
I understand this code together with the
explanation in the book that the idea is to build a percentage return and then a
geometric compounded return.
I send a note to the author and I understand now as
follow:
Profit = SellPrice / BuyPrice
CumProfit = Ref(CumProfit, -1) *
Profit
For example if you have two trades, one winner of
10% and one loser of -10% starting from 100 I will have
Trade 1 : Profit = 1.1
Trade 2 Profit = 0.9
CumProfit = 1.1 * 0.9 = 0.99
which means 100 * 1.1 = 110 then 110 * 0.9 = 99 and
99 / 100 = 0.99.
Thanks for your help.
Bernard Bourée<A
href="">bernard@xxxx
<BLOCKQUOTE
>
----- Original Message -----
<DIV
>From:
DIMITRIS
TSOKAKIS
To: <A title=amibroker@xxxxxxxxxx
href="">amibroker@xxxxxxxxxxxxxxx
Sent: Wednesday, August 15, 2001 2:15
PM
Subject: [amibroker] Re: Formula
Bernard,a.P = 1 + (SellPrice - BuyPrice) /
BuyPrice;is EXACTLY equivalent
toP=SellPrice/BuyPrice;becauseP=1+(S-B)/B=(B+S-B)/B=S/Bb.
What is CP in words?This will help perhaps to continue.If I take
verbatim theCP = CP * P;meansCP-CP*P=0, IECP*(1-P)=0,
IEeither CP=0 or P=1Better say what is CP in words.Dimitris
Tsokakis--- In amibroker@xxxx, Bernard Bourée <bernard@xxxx>
wrote:> Hello,> > I have the following code:>
> P = 1 + (SellPrice - BuyPrice) / BuyPrice;> CP = CP *
P;> > > CP need to be initialised to 1.> How can I
do that. If I code > CP = IIF( Cum(1) == 1, 1, CP);> I have an
error since CP is unknown and should not be placed in the right part of
the formula since is still not defined.> > Someone has an idea
?> > Thanks> Bernard Bourée>
bernard@xxxxYour
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